1) What is a Machine?
A machine is a device that makes work easier by:
- Multiplying force (so you can lift heavy stuff with less effort)
- Changing the direction of force (pulling down to lift up)
- Increasing the speed of work
Simple machines you already know — lever, pulley, inclined plane, screw, wedge, wheel and axle. But in ICSE Class 10, we focus on levers and pulleys mainly.
2) Key Terms — Load, Effort, Fulcrum
| Term | Symbol | Meaning | Unit |
|---|---|---|---|
| Load | L | The weight or resistance that the machine has to overcome | N, kgf, gf |
| Effort | E | The force applied on the machine to overcome the load | N, kgf, gf |
| Fulcrum / Pivot | — | The fixed point about which the machine rotates | — |
3) Mechanical Advantage (MA)
MA tells you how many times the machine multiplies the applied effort. It's the ratio of load to effort.
M.A. = Load / Effort = L / E
MA has NO unit (it's a ratio — same units cancel out)
Conditions of MA — This Is What ICSE Asks
| Condition | What it means | Example |
|---|---|---|
| MA > 1 | Machine multiplies force. You apply less effort to lift more load. | Nutcracker, crowbar, movable pulley |
| MA = 1 | Machine just changes direction. Effort = Load. | Single fixed pulley |
| MA < 1 | Machine doesn't multiply force — used for speed or range. | Class III lever (tweezers, fishing rod) |
4) Velocity Ratio (VR)
VR is the ratio of the distance moved by the effort to the distance moved by the load in the same time.
V.R. = Distance moved by effort / Distance moved by load
VR also has NO unit
VR depends only on the design of the machine, not on friction. So VR is always constant for a given machine. This is a key difference from MA — MA can change if there's friction, but VR stays fixed.
5) Efficiency (η)
No machine is perfect — some energy is always wasted overcoming friction. Efficiency tells you how much of the input work is usefully converted into output work.
Formula + Derivation
Work input = Effort × distance moved by effort = E × dE
Work output = Load × distance moved by load = L × dL
Efficiency (η) = Work output / Work input
= (L × dL) / (E × dE)
= (L / E) × (dL / dE)
= MA × (1 / VR) = MA / VR
η = MA / VR
In percentage: η% = (MA / VR) × 100%
For an ideal machine (no friction): MA = VR, so η = 1 or 100%. But in real life, η is always less than 100%.
6) Relationship Between MA, VR, and η
MA = VR × η
MA < VR for a real machine (since η < 1)
MA = VR for an ideal machine (η = 1)
7) Work Output and Work Input
Work input = work done by the effort on the machine.
Work output = useful work done by the machine on the load.
- Work input > Work output (always, because of friction)
- Wasted work = Work input - Work output
- Wasted work is usually used to overcome friction
8) Principle of a Machine
The principle of a machine states that: "In an ideal machine (no friction), the work done by the effort (work input) is equal to the work done by the load (work output)."
For an ideal machine: Work input = Work output
E × dE = L × dL
L / E = dE / dL → MA = VR
9) Levers
A lever is a rigid bar that rotates about a fixed point (fulcrum). Levers are classified into three classes based on the relative positions of load, effort, and fulcrum.
Class I Lever — Fulcrum in the Middle
Fulcrum between Load and Effort
- MA > 1 if effort arm > load arm (like a crowbar)
- MA = 1 if effort arm = load arm (like a see-saw balanced)
- MA < 1 if effort arm < load arm
- Examples: Crowbar, see-saw, scissors, pliers, pincer
Class II Lever — Load in the Middle
Load between Fulcrum and Effort
- Effort arm > Load arm always → MA > 1 always
- These levers always multiply force
- Examples: Nutcracker, bottle opener, wheelbarrow, punching shears
Class III Lever — Effort in the Middle
Effort between Fulcrum and Load
- Effort arm < Load arm always → MA < 1 always
- These levers don't multiply force — they increase speed/range of motion
- Examples: Tweezers, fishing rod, tongs, human forearm, broom
| Class | Arrangement | MA | Examples |
|---|---|---|---|
| I | F—L—E or L—F—E | Can be >1, =1, or <1 | Crowbar, see-saw, scissors |
| II | F—E—L (L in middle) | Always > 1 | Nutcracker, wheelbarrow |
| III | F—L—E (E in middle) | Always < 1 | Tweezers, fishing rod |
10) Pulley Systems
Single Fixed Pulley
- Pulley is fixed to a support. You pull down to lift up.
- MA = 1, VR = 1
- Does NOT multiply force — just changes direction of effort
- Efficiency η < 100% due to friction
Single Movable Pulley
- Pulley moves with the load. One end of the string is fixed, effort is applied at the other end.
- MA = 2, VR = 2 (ideally)
- Effort needed is half the load (in ideal case)
- The load is supported by 2 segments of the string
Block and Tackle System
The block and tackle system uses multiple pulleys arranged in two blocks — one fixed and one movable. The combination multiplies force significantly.
For a block and tackle with n pulleys in each block (or n rope segments):
VR = n (number of rope segments supporting the load)
MA = n × η (ideally MA = n if η = 100%)
Effort E = L / MA = L / (n × η)
How to find VR: Simply count the number of rope segments that support the movable (lower) block. That number is your VR.
| System | MA (ideal) | VR | Change direction? |
|---|---|---|---|
| Single fixed pulley | 1 | 1 | Yes |
| Single movable pulley | 2 | 2 | No |
| Block and tackle (2 pulleys each) | 4 | 4 | Yes |
| Block and tackle (n segments) | n | n | Depends on design |
11) Solved Numericals
Numerical 1 — Lever (Class I)
A crowbar of length 120 cm has its fulcrum at 20 cm from the load. A load of 60 kgf is to be lifted. Calculate the effort required and MA.
Load arm = distance from fulcrum to load = 20 cm
Effort arm = 120 - 20 = 100 cm
MA = Effort arm / Load arm = 100 / 20 = 5
MA = L / E → 5 = 60 / E → E = 12 kgf
So just 12 kgf lifts 60 kgf. That's the power of levers!
Numerical 2 — Pulley Efficiency
A single movable pulley is used to lift a load of 100 kgf. The effort required is 55 kgf. Find MA, VR, and efficiency.
MA = L / E = 100 / 55 = 1.82
For a single movable pulley, VR = 2 (2 rope segments support the load)
η = MA / VR = 1.82 / 2 = 0.91 = 91%
Numerical 3 — Block and Tackle
A block and tackle system has 4 pulleys in each block (total 4 rope segments supporting the load). A load of 200 kgf is lifted with an effort of 60 kgf. Find MA, VR, and efficiency.
MA = L / E = 200 / 60 = 3.33
VR = number of rope segments = 4
η = MA / VR = 3.33 / 4 = 0.833 = 83.3%
Work input = E × dE, Work output = L × dL
If load rises 1 m, effort moves 4 m (since VR = 4)
Numerical 4 — MA from Lever Diagram
In a pair of scissors, the load arm is 4 cm and the effort arm is 12 cm. Find its MA. Is it a force multiplier or speed multiplier?
MA = Effort arm / Load arm = 12 / 4 = 3
MA > 1 → it's a force multiplier
Fun fact: Scissors are actually two Class I levers joined together. Most scissors have MA > 1 so cutting is easier.
12) Quick Revision — Night Before the Exam
- MA = L/E — ratio of load to effort (no unit)
- VR = dE / dL — ratio of distances (design-dependent)
- Efficiency η = MA/VR — always < 1 for real machines
- Ideal machine: MA = VR, η = 100%
- Principle of machine: Work input = Work output (ideal)
- Levers: Class I (fulcrum middle), Class II (load middle, MA>1), Class III (effort middle, MA<1)
- Single fixed pulley: MA = VR = 1 (changes direction only)
- Single movable pulley: MA = VR = 2 (multiplies force by 2)
- Block and tackle: VR = number of rope segments supporting the movable block
13) All Formulas at One Glance
MA = Load / Effort = L / E
VR = dE / dL
Efficiency η = Work output / Work input = MA / VR
η% = (MA / VR) × 100%
For levers: MA = Effort arm / Load arm
For ideal machine: MA = VR
For block and tackle: VR = n (number of rope segments)
Work input = E × dE
Work output = L × dL
Wasted work = Work input - Work output